Line slope calculator 8x+y=16


Enter coordinates of two different points:

Straight line given by points A[1; 8] and B[2; 0]

Calculation:

Slope-intercept form of line: y = -8x+16

Canonical form of the line equation: 8x+y-16 = 0

Parametric form of the line equation:
x = t+1
y = -8t+8      ; t ∈ R

Slope: m = -8

Slope angle of line: φ = -82°52'30″ = -1.4464 rad

X intercept: x0 = 2

Y intercept: y0 = q = 16

Distance line from the origin: d0 = 1.9846

The length of the segment AB: |AB| = 8.0623

Vector: AB = (1; -8)

Normal vector: n = (8; 1)

Midpoint of the segment AB: M = [1.5; 4]

Perpendicular Bisector equation: x-8y+30.5 = 0


Vector OA = (1; 8) ;   |OA| = 8.0623
Vector OB = (2; 0) ;   |OB| = 2
Scalar product OA .OB = 2
Angle ∠ AOB = 82°52'30″ = 1.4464 rad