Line slope calculator 8x+y=16
Straight line given by points A[1; 8] and B[2; 0]
Calculation:
Slope: m = -8Slope-intercept form of line: y = -8x+16
Canonical form of the line equation: 8x+y-16 = 0
Parametric form of the line equation:
x = t+1
y = -8t+8 ; t ∈ R
Slope angle of line: φ = -82°52'30″ = -1.4464 rad
X intercept: x0 = 2
Y intercept: y0 = q = 16
Distance line from the origin: d0 = 1.9846
The length of the segment AB: |AB| = 8.0623
Vector: AB = (1; -8)
Normal vector: n = (8; 1)
Midpoint of the segment AB: M = [1.5; 4]
Perpendicular Bisector equation: x-8y+30.5 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (2; 0) ; |OB| = 2
Scalar product OA .OB = 2
Angle ∠ AOB = 82°52'30″ = 1.4464 rad