Line slope calculator 7x+y=15
Straight line given by points A[1; 8] and B[2; 1]
Calculation:
Slope: m = -7Slope-intercept form of line: y = -7x+15
Canonical form of the line equation: 7x+y-15 = 0
Parametric form of the line equation:
x = t+1
y = -7t+8 ; t ∈ R
Slope angle of line: φ = -81°52'12″ = -1.4289 rad
X intercept: x0 = 2.1429
Y intercept: y0 = q = 15
Distance line from the origin: d0 = 2.1213
The length of the segment AB: |AB| = 7.0711
Vector: AB = (1; -7)
Normal vector: n = (7; 1)
Midpoint of the segment AB: M = [1.5; 4.5]
Perpendicular Bisector equation: x-7y+30 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (2; 1) ; |OB| = 2.2361
Scalar product OA .OB = 10
Angle ∠ AOB = 56°18'36″ = 0.9828 rad