Line slope calculator 6x+y=14
Straight line given by points A[1; 8] and B[2; 2]
Calculation:
Slope: m = -6Slope-intercept form of line: y = -6x+14
Canonical form of the line equation: 6x+y-14 = 0
Parametric form of the line equation:
x = t+1
y = -6t+8 ; t ∈ R
Slope angle of line: φ = -80°32'16″ = -1.4056 rad
X intercept: x0 = 2.3333
Y intercept: y0 = q = 14
Distance line from the origin: d0 = 2.3016
The length of the segment AB: |AB| = 6.0828
Vector: AB = (1; -6)
Normal vector: n = (6; 1)
Midpoint of the segment AB: M = [1.5; 5]
Perpendicular Bisector equation: x-6y+28.5 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (2; 2) ; |OB| = 2.8284
Scalar product OA .OB = 18
Angle ∠ AOB = 37°52'30″ = 0.661 rad