Line slope calculator 5x+y=13


Enter coordinates of two different points:

Straight line given by points A[1; 8] and B[2; 3]

Calculation:

Slope-intercept form of line: y = -5x+13

Canonical form of the line equation: 5x+y-13 = 0

Parametric form of the line equation:
x = t+1
y = -5t+8      ; t ∈ R

Slope: m = -5

Slope angle of line: φ = -78°41'24″ = -1.3734 rad

X intercept: x0 = 2.6

Y intercept: y0 = q = 13

Distance line from the origin: d0 = 2.5495

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; -5)

Normal vector: n = (5; 1)

Midpoint of the segment AB: M = [1.5; 5.5]

Perpendicular Bisector equation: x-5y+26 = 0


Vector OA = (1; 8) ;   |OA| = 8.0623
Vector OB = (2; 3) ;   |OB| = 3.6056
Scalar product OA .OB = 26
Angle ∠ AOB = 26°33'54″ = 0.4636 rad