Line slope calculator 5x+y=13
Straight line given by points A[1; 8] and B[2; 3]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+13
Canonical form of the line equation: 5x+y-13 = 0
Parametric form of the line equation:
x = t+1
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 2.6
Y intercept: y0 = q = 13
Distance line from the origin: d0 = 2.5495
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [1.5; 5.5]
Perpendicular Bisector equation: x-5y+26 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (2; 3) ; |OB| = 3.6056
Scalar product OA .OB = 26
Angle ∠ AOB = 26°33'54″ = 0.4636 rad