Line slope calculator 3x+y=11
Straight line given by points A[1; 8] and B[2; 5]
Calculation:
Slope: m = -3Slope-intercept form of line: y = -3x+11
Canonical form of the line equation: 3x+y-11 = 0
Parametric form of the line equation:
x = t+1
y = -3t+8 ; t ∈ R
Slope angle of line: φ = -71°33'54″ = -1.249 rad
X intercept: x0 = 3.6667
Y intercept: y0 = q = 11
Distance line from the origin: d0 = 3.4785
The length of the segment AB: |AB| = 3.1623
Vector: AB = (1; -3)
Normal vector: n = (3; 1)
Midpoint of the segment AB: M = [1.5; 6.5]
Perpendicular Bisector equation: x-3y+18 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (2; 5) ; |OB| = 5.3852
Scalar product OA .OB = 42
Angle ∠ AOB = 14°40'35″ = 0.2562 rad