Line slope calculator 3x+2y=19
Straight line given by points A[1; 8] and B[3; 5]
Calculation:
Slope: m = -1.5Slope-intercept form of line: y = -1.5x+9.5
Canonical form of the line equation: 3x+2y-19 = 0
Parametric form of the line equation:
x = 2t+1
y = -3t+8 ; t ∈ R
Slope angle of line: φ = -56°18'36″ = -0.9828 rad
X intercept: x0 = 6.3333
Y intercept: y0 = q = 9.5
Distance line from the origin: d0 = 5.2697
The length of the segment AB: |AB| = 3.6056
Vector: AB = (2; -3)
Normal vector: n = (3; 2)
Midpoint of the segment AB: M = [2; 6.5]
Perpendicular Bisector equation: 2x-3y+15.5 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (3; 5) ; |OB| = 5.831
Scalar product OA .OB = 43
Angle ∠ AOB = 23°50'19″ = 0.4161 rad