Line slope calculator 8x+3y=32
Straight line given by points A[1; 8] and B[4; 0]
Calculation:
Slope: m = -2.6667Slope-intercept form of line: y = -2.6667x+10.6667
Canonical form of the line equation: 8x+3y-32 = 0
Parametric form of the line equation:
x = 3t+1
y = -8t+8 ; t ∈ R
Slope angle of line: φ = -69°26'38″ = -1.212 rad
X intercept: x0 = 4
Y intercept: y0 = q = 10.6667
Distance line from the origin: d0 = 3.7453
The length of the segment AB: |AB| = 8.544
Vector: AB = (3; -8)
Normal vector: n = (8; 3)
Midpoint of the segment AB: M = [2.5; 4]
Perpendicular Bisector equation: 3x-8y+24.5 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (4; 0) ; |OB| = 4
Scalar product OA .OB = 4
Angle ∠ AOB = 82°52'30″ = 1.4464 rad