Line slope calculator 8x+3y=32


Enter coordinates of two different points:

Straight line given by points A[1; 8] and B[4; 0]

Calculation:

Slope-intercept form of line: y = -2.6667x+10.6667

Canonical form of the line equation: 8x+3y-32 = 0

Parametric form of the line equation:
x = 3t+1
y = -8t+8      ; t ∈ R

Slope: m = -2.6667

Slope angle of line: φ = -69°26'38″ = -1.212 rad

X intercept: x0 = 4

Y intercept: y0 = q = 10.6667

Distance line from the origin: d0 = 3.7453

The length of the segment AB: |AB| = 8.544

Vector: AB = (3; -8)

Normal vector: n = (8; 3)

Midpoint of the segment AB: M = [2.5; 4]

Perpendicular Bisector equation: 3x-8y+24.5 = 0


Vector OA = (1; 8) ;   |OA| = 8.0623
Vector OB = (4; 0) ;   |OB| = 4
Scalar product OA .OB = 4
Angle ∠ AOB = 82°52'30″ = 1.4464 rad