Line slope calculator 5x+3y=29


Enter coordinates of two different points:

Straight line given by points A[1; 8] and B[4; 3]

Calculation:

Slope-intercept form of line: y = -1.6667x+9.6667

Canonical form of the line equation: 5x+3y-29 = 0

Parametric form of the line equation:
x = 3t+1
y = -5t+8      ; t ∈ R

Slope: m = -1.6667

Slope angle of line: φ = -59°2'10″ = -1.0304 rad

X intercept: x0 = 5.8

Y intercept: y0 = q = 9.6667

Distance line from the origin: d0 = 4.9735

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; -5)

Normal vector: n = (5; 3)

Midpoint of the segment AB: M = [2.5; 5.5]

Perpendicular Bisector equation: 3x-5y+20 = 0


Vector OA = (1; 8) ;   |OA| = 8.0623
Vector OB = (4; 3) ;   |OB| = 5
Scalar product OA .OB = 28
Angle ∠ AOB = 46°18″ = 0.8029 rad