Line slope calculator 2x+3y=26
Straight line given by points A[1; 8] and B[4; 6]
Calculation:
Slope: m = -0.6667Slope-intercept form of line: y = -0.6667x+8.6667
Canonical form of the line equation: 2x+3y-26 = 0
Parametric form of the line equation:
x = 3t+1
y = -2t+8 ; t ∈ R
Slope angle of line: φ = -33°41'24″ = -0.588 rad
X intercept: x0 = 13
Y intercept: y0 = q = 8.6667
Distance line from the origin: d0 = 7.2111
The length of the segment AB: |AB| = 3.6056
Vector: AB = (3; -2)
Normal vector: n = (2; 3)
Midpoint of the segment AB: M = [2.5; 7]
Perpendicular Bisector equation: 3x-2y+6.5 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (4; 6) ; |OB| = 7.2111
Scalar product OA .OB = 52
Angle ∠ AOB = 26°33'54″ = 0.4636 rad