Line slope calculator 7x+4y=39
Straight line given by points A[1; 8] and B[5; 1]
Calculation:
Slope: m = -1.75Slope-intercept form of line: y = -1.75x+9.75
Canonical form of the line equation: 7x+4y-39 = 0
Parametric form of the line equation:
x = 4t+1
y = -7t+8 ; t ∈ R
Slope angle of line: φ = -60°15'18″ = -1.0517 rad
X intercept: x0 = 5.5714
Y intercept: y0 = q = 9.75
Distance line from the origin: d0 = 4.8374
The length of the segment AB: |AB| = 8.0623
Vector: AB = (4; -7)
Normal vector: n = (7; 4)
Midpoint of the segment AB: M = [3; 4.5]
Perpendicular Bisector equation: 4x-7y+19.5 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (5; 1) ; |OB| = 5.099
Scalar product OA .OB = 13
Angle ∠ AOB = 71°33'54″ = 1.249 rad