Line slope calculator 7x+4y=39


Enter coordinates of two different points:

Straight line given by points A[1; 8] and B[5; 1]

Calculation:

Slope-intercept form of line: y = -1.75x+9.75

Canonical form of the line equation: 7x+4y-39 = 0

Parametric form of the line equation:
x = 4t+1
y = -7t+8      ; t ∈ R

Slope: m = -1.75

Slope angle of line: φ = -60°15'18″ = -1.0517 rad

X intercept: x0 = 5.5714

Y intercept: y0 = q = 9.75

Distance line from the origin: d0 = 4.8374

The length of the segment AB: |AB| = 8.0623

Vector: AB = (4; -7)

Normal vector: n = (7; 4)

Midpoint of the segment AB: M = [3; 4.5]

Perpendicular Bisector equation: 4x-7y+19.5 = 0


Vector OA = (1; 8) ;   |OA| = 8.0623
Vector OB = (5; 1) ;   |OB| = 5.099
Scalar product OA .OB = 13
Angle ∠ AOB = 71°33'54″ = 1.249 rad