Line slope calculator 5x+4y=37
Straight line given by points A[1; 8] and B[5; 3]
Calculation:
Slope: m = -1.25Slope-intercept form of line: y = -1.25x+9.25
Canonical form of the line equation: 5x+4y-37 = 0
Parametric form of the line equation:
x = 4t+1
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -51°20'25″ = -0.8961 rad
X intercept: x0 = 7.4
Y intercept: y0 = q = 9.25
Distance line from the origin: d0 = 5.7784
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; -5)
Normal vector: n = (5; 4)
Midpoint of the segment AB: M = [3; 5.5]
Perpendicular Bisector equation: 4x-5y+15.5 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (5; 3) ; |OB| = 5.831
Scalar product OA .OB = 29
Angle ∠ AOB = 51°54'40″ = 0.906 rad