Line slope calculator 8x+5y=48
Straight line given by points A[1; 8] and B[6; 0]
Calculation:
Slope: m = -1.6Slope-intercept form of line: y = -1.6x+9.6
Canonical form of the line equation: 8x+5y-48 = 0
Parametric form of the line equation:
x = 5t+1
y = -8t+8 ; t ∈ R
Slope angle of line: φ = -57°59'41″ = -1.0122 rad
X intercept: x0 = 6
Y intercept: y0 = q = 9.6
Distance line from the origin: d0 = 5.088
The length of the segment AB: |AB| = 9.434
Vector: AB = (5; -8)
Normal vector: n = (8; 5)
Midpoint of the segment AB: M = [3.5; 4]
Perpendicular Bisector equation: 5x-8y+14.5 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (6; 0) ; |OB| = 6
Scalar product OA .OB = 6
Angle ∠ AOB = 82°52'30″ = 1.4464 rad