Line slope calculator 8x+5y=48


Enter coordinates of two different points:

Straight line given by points A[1; 8] and B[6; 0]

Calculation:

Slope-intercept form of line: y = -1.6x+9.6

Canonical form of the line equation: 8x+5y-48 = 0

Parametric form of the line equation:
x = 5t+1
y = -8t+8      ; t ∈ R

Slope: m = -1.6

Slope angle of line: φ = -57°59'41″ = -1.0122 rad

X intercept: x0 = 6

Y intercept: y0 = q = 9.6

Distance line from the origin: d0 = 5.088

The length of the segment AB: |AB| = 9.434

Vector: AB = (5; -8)

Normal vector: n = (8; 5)

Midpoint of the segment AB: M = [3.5; 4]

Perpendicular Bisector equation: 5x-8y+14.5 = 0


Vector OA = (1; 8) ;   |OA| = 8.0623
Vector OB = (6; 0) ;   |OB| = 6
Scalar product OA .OB = 6
Angle ∠ AOB = 82°52'30″ = 1.4464 rad