Line slope calculator 7x+5y=47
Straight line given by points A[1; 8] and B[6; 1]
Calculation:
Slope: m = -1.4Slope-intercept form of line: y = -1.4x+9.4
Canonical form of the line equation: 7x+5y-47 = 0
Parametric form of the line equation:
x = 5t+1
y = -7t+8 ; t ∈ R
Slope angle of line: φ = -54°27'44″ = -0.9505 rad
X intercept: x0 = 6.7143
Y intercept: y0 = q = 9.4
Distance line from the origin: d0 = 5.4636
The length of the segment AB: |AB| = 8.6023
Vector: AB = (5; -7)
Normal vector: n = (7; 5)
Midpoint of the segment AB: M = [3.5; 4.5]
Perpendicular Bisector equation: 5x-7y+14 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (6; 1) ; |OB| = 6.0828
Scalar product OA .OB = 14
Angle ∠ AOB = 73°24'46″ = 1.2813 rad