Line slope calculator 5x+6y=53


Enter coordinates of two different points:

Straight line given by points A[1; 8] and B[7; 3]

Calculation:

Slope-intercept form of line: y = -0.8333x+8.8333

Canonical form of the line equation: 5x+6y-53 = 0

Parametric form of the line equation:
x = 6t+1
y = -5t+8      ; t ∈ R

Slope: m = -0.8333

Slope angle of line: φ = -39°48'20″ = -0.6947 rad

X intercept: x0 = 10.6

Y intercept: y0 = q = 8.8333

Distance line from the origin: d0 = 6.786

The length of the segment AB: |AB| = 7.8102

Vector: AB = (6; -5)

Normal vector: n = (5; 6)

Midpoint of the segment AB: M = [4; 5.5]

Perpendicular Bisector equation: 6x-5y+3.5 = 0


Vector OA = (1; 8) ;   |OA| = 8.0623
Vector OB = (7; 3) ;   |OB| = 7.6158
Scalar product OA .OB = 31
Angle ∠ AOB = 59°40'35″ = 1.0415 rad