Line slope calculator 8x+7y=64
Straight line given by points A[1; 8] and B[8; 0]
Calculation:
Slope: m = -1.1429Slope-intercept form of line: y = -1.1429x+9.1429
Canonical form of the line equation: 8x+7y-64 = 0
Parametric form of the line equation:
x = 7t+1
y = -8t+8 ; t ∈ R
Slope angle of line: φ = -48°48'51″ = -0.852 rad
X intercept: x0 = 8
Y intercept: y0 = q = 9.1429
Distance line from the origin: d0 = 6.0206
The length of the segment AB: |AB| = 10.6301
Vector: AB = (7; -8)
Normal vector: n = (8; 7)
Midpoint of the segment AB: M = [4.5; 4]
Perpendicular Bisector equation: 7x-8y+0.5 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (8; 0) ; |OB| = 8
Scalar product OA .OB = 8
Angle ∠ AOB = 82°52'30″ = 1.4464 rad