Line slope calculator 10x-3y=20


Enter coordinates of two different points:

Straight line given by points A[2; 0] and B[5; 10]

Calculation:

Slope-intercept form of line: y = 3.3333x-6.6667

Canonical form of the line equation: 10x-3y-20 = 0

Parametric form of the line equation:
x = 3t+2
y = 10t      ; t ∈ R

Slope: m = 3.3333

Slope angle of line: φ = 73°18'3″ = 1.2793 rad

X intercept: x0 = 2

Y intercept: y0 = q = -6.6667

Distance line from the origin: d0 = 1.9157

The length of the segment AB: |AB| = 10.4403

Vector: AB = (3; 10)

Normal vector: n = (10; -3)

Midpoint of the segment AB: M = [3.5; 5]

Perpendicular Bisector equation: 3x+10y-60.5 = 0


Vector OA = (2; 0) ;   |OA| = 2
Vector OB = (5; 10) ;   |OB| = 11.1803
Scalar product OA .OB = 10
Angle ∠ AOB = 63°26'6″ = 1.1071 rad