Line slope calculator 5x-3y=10


Enter coordinates of two different points:

Straight line given by points A[2; 0] and B[5; 5]

Calculation:

Slope-intercept form of line: y = 1.6667x-3.3333

Canonical form of the line equation: 5x-3y-10 = 0

Parametric form of the line equation:
x = 3t+2
y = 5t      ; t ∈ R

Slope: m = 1.6667

Slope angle of line: φ = 59°2'10″ = 1.0304 rad

X intercept: x0 = 2

Y intercept: y0 = q = -3.3333

Distance line from the origin: d0 = 1.715

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; 5)

Normal vector: n = (5; -3)

Midpoint of the segment AB: M = [3.5; 2.5]

Perpendicular Bisector equation: 3x+5y-23 = 0


Vector OA = (2; 0) ;   |OA| = 2
Vector OB = (5; 5) ;   |OB| = 7.0711
Scalar product OA .OB = 10
Angle ∠ AOB = 45° = 0.7854 rad