Line slope calculator 8x-5y=16


Enter coordinates of two different points:

Straight line given by points A[2; 0] and B[7; 8]

Calculation:

Slope-intercept form of line: y = 1.6x-3.2

Canonical form of the line equation: 8x-5y-16 = 0

Parametric form of the line equation:
x = 5t+2
y = 8t      ; t ∈ R

Slope: m = 1.6

Slope angle of line: φ = 57°59'41″ = 1.0122 rad

X intercept: x0 = 2

Y intercept: y0 = q = -3.2

Distance line from the origin: d0 = 1.696

The length of the segment AB: |AB| = 9.434

Vector: AB = (5; 8)

Normal vector: n = (8; -5)

Midpoint of the segment AB: M = [4.5; 4]

Perpendicular Bisector equation: 5x+8y-54.5 = 0


Vector OA = (2; 0) ;   |OA| = 2
Vector OB = (7; 8) ;   |OB| = 10.6301
Scalar product OA .OB = 14
Angle ∠ AOB = 48°48'51″ = 0.852 rad