Line slope calculator 8x-5y=16
Straight line given by points A[2; 0] and B[7; 8]
Calculation:
Slope: m = 1.6Slope-intercept form of line: y = 1.6x-3.2
Canonical form of the line equation: 8x-5y-16 = 0
Parametric form of the line equation:
x = 5t+2
y = 8t ; t ∈ R
Slope angle of line: φ = 57°59'41″ = 1.0122 rad
X intercept: x0 = 2
Y intercept: y0 = q = -3.2
Distance line from the origin: d0 = 1.696
The length of the segment AB: |AB| = 9.434
Vector: AB = (5; 8)
Normal vector: n = (8; -5)
Midpoint of the segment AB: M = [4.5; 4]
Perpendicular Bisector equation: 5x+8y-54.5 = 0
Vector OA = (2; 0) ; |OA| = 2
Vector OB = (7; 8) ; |OB| = 10.6301
Scalar product OA .OB = 14
Angle ∠ AOB = 48°48'51″ = 0.852 rad