Line slope calculator x+8y=10


Enter coordinates of two different points:

Straight line given by points A[2; 1] and B[10; 0]

Calculation:

Slope-intercept form of line: y = -0.125x+1.25

Canonical form of the line equation: x+8y-10 = 0

Parametric form of the line equation:
x = 8t+2
y = -t+1      ; t ∈ R

Slope: m = -0.125

Slope angle of line: φ = -7°7'30″ = -0.1244 rad

X intercept: x0 = 10

Y intercept: y0 = q = 1.25

Distance line from the origin: d0 = 1.2403

The length of the segment AB: |AB| = 8.0623

Vector: AB = (8; -1)

Normal vector: n = (1; 8)

Midpoint of the segment AB: M = [6; 0.5]

Perpendicular Bisector equation: 8x-y-47.5 = 0


Vector OA = (2; 1) ;   |OA| = 2.2361
Vector OB = (10; 0) ;   |OB| = 10
Scalar product OA .OB = 20
Angle ∠ AOB = 26°33'54″ = 0.4636 rad