Line slope calculator x+8y=10
Straight line given by points A[2; 1] and B[10; 0]
Calculation:
Slope: m = -0.125Slope-intercept form of line: y = -0.125x+1.25
Canonical form of the line equation: x+8y-10 = 0
Parametric form of the line equation:
x = 8t+2
y = -t+1 ; t ∈ R
Slope angle of line: φ = -7°7'30″ = -0.1244 rad
X intercept: x0 = 10
Y intercept: y0 = q = 1.25
Distance line from the origin: d0 = 1.2403
The length of the segment AB: |AB| = 8.0623
Vector: AB = (8; -1)
Normal vector: n = (1; 8)
Midpoint of the segment AB: M = [6; 0.5]
Perpendicular Bisector equation: 8x-y-47.5 = 0
Vector OA = (2; 1) ; |OA| = 2.2361
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 20
Angle ∠ AOB = 26°33'54″ = 0.4636 rad