Line slope calculator x-8y=-6
Straight line given by points A[2; 1] and B[10; 2]
Calculation:
Slope: m = 0.125Slope-intercept form of line: y = 0.125x+0.75
Canonical form of the line equation: x-8y+6 = 0
Parametric form of the line equation:
x = 8t+2
y = t+1 ; t ∈ R
Slope angle of line: φ = 7°7'30″ = 0.1244 rad
X intercept: x0 = -6
Y intercept: y0 = q = 0.75
Distance line from the origin: d0 = 0.7442
The length of the segment AB: |AB| = 8.0623
Vector: AB = (8; 1)
Normal vector: n = (1; -8)
Midpoint of the segment AB: M = [6; 1.5]
Perpendicular Bisector equation: 8x+y-49.5 = 0
Vector OA = (2; 1) ; |OA| = 2.2361
Vector OB = (10; 2) ; |OB| = 10.198
Scalar product OA .OB = 22
Angle ∠ AOB = 15°15'18″ = 0.2663 rad