Line slope calculator x+3y=5
Straight line given by points A[2; 1] and B[5; 0]
Calculation:
Slope: m = -0.3333Slope-intercept form of line: y = -0.3333x+1.6667
Canonical form of the line equation: x+3y-5 = 0
Parametric form of the line equation:
x = 3t+2
y = -t+1 ; t ∈ R
Slope angle of line: φ = -18°26'6″ = -0.3218 rad
X intercept: x0 = 5
Y intercept: y0 = q = 1.6667
Distance line from the origin: d0 = 1.5811
The length of the segment AB: |AB| = 3.1623
Vector: AB = (3; -1)
Normal vector: n = (1; 3)
Midpoint of the segment AB: M = [3.5; 0.5]
Perpendicular Bisector equation: 3x-y-10 = 0
Vector OA = (2; 1) ; |OA| = 2.2361
Vector OB = (5; 0) ; |OB| = 5
Scalar product OA .OB = 10
Angle ∠ AOB = 26°33'54″ = 0.4636 rad