Line slope calculator x-3y=-1
Straight line given by points A[2; 1] and B[5; 2]
Calculation:
Slope: m = 0.3333Slope-intercept form of line: y = 0.3333x+0.3333
Canonical form of the line equation: x-3y+1 = 0
Parametric form of the line equation:
x = 3t+2
y = t+1 ; t ∈ R
Slope angle of line: φ = 18°26'6″ = 0.3218 rad
X intercept: x0 = -1
Y intercept: y0 = q = 0.3333
Distance line from the origin: d0 = 0.3162
The length of the segment AB: |AB| = 3.1623
Vector: AB = (3; 1)
Normal vector: n = (1; -3)
Midpoint of the segment AB: M = [3.5; 1.5]
Perpendicular Bisector equation: 3x+y-12 = 0
Vector OA = (2; 1) ; |OA| = 2.2361
Vector OB = (5; 2) ; |OB| = 5.3852
Scalar product OA .OB = 12
Angle ∠ AOB = 4°45'49″ = 0.0831 rad