Line slope calculator 4x-3y=5
Straight line given by points A[2; 1] and B[5; 5]
Calculation:
Slope: m = 1.3333Slope-intercept form of line: y = 1.3333x-1.6667
Canonical form of the line equation: 4x-3y-5 = 0
Parametric form of the line equation:
x = 3t+2
y = 4t+1 ; t ∈ R
Slope angle of line: φ = 53°7'48″ = 0.9273 rad
X intercept: x0 = 1.25
Y intercept: y0 = q = -1.6667
Distance line from the origin: d0 = 1
The length of the segment AB: |AB| = 5
Vector: AB = (3; 4)
Normal vector: n = (4; -3)
Midpoint of the segment AB: M = [3.5; 3]
Perpendicular Bisector equation: 3x+4y-22.5 = 0
Vector OA = (2; 1) ; |OA| = 2.2361
Vector OB = (5; 5) ; |OB| = 7.0711
Scalar product OA .OB = 15
Angle ∠ AOB = 18°26'6″ = 0.3218 rad