Line slope calculator 7x-3y=11


Enter coordinates of two different points:

Straight line given by points A[2; 1] and B[5; 8]

Calculation:

Slope-intercept form of line: y = 2.3333x-3.6667

Canonical form of the line equation: 7x-3y-11 = 0

Parametric form of the line equation:
x = 3t+2
y = 7t+1      ; t ∈ R

Slope: m = 2.3333

Slope angle of line: φ = 66°48'5″ = 1.1659 rad

X intercept: x0 = 1.5714

Y intercept: y0 = q = -3.6667

Distance line from the origin: d0 = 1.4444

The length of the segment AB: |AB| = 7.6158

Vector: AB = (3; 7)

Normal vector: n = (7; -3)

Midpoint of the segment AB: M = [3.5; 4.5]

Perpendicular Bisector equation: 3x+7y-42 = 0


Vector OA = (2; 1) ;   |OA| = 2.2361
Vector OB = (5; 8) ;   |OB| = 9.434
Scalar product OA .OB = 18
Angle ∠ AOB = 31°25'46″ = 0.5485 rad