Line slope calculator x+4y=6
Straight line given by points A[2; 1] and B[6; 0]
Calculation:
Slope: m = -0.25Slope-intercept form of line: y = -0.25x+1.5
Canonical form of the line equation: x+4y-6 = 0
Parametric form of the line equation:
x = 4t+2
y = -t+1 ; t ∈ R
Slope angle of line: φ = -14°2'10″ = -0.245 rad
X intercept: x0 = 6
Y intercept: y0 = q = 1.5
Distance line from the origin: d0 = 1.4552
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; -1)
Normal vector: n = (1; 4)
Midpoint of the segment AB: M = [4; 0.5]
Perpendicular Bisector equation: 4x-y-15.5 = 0
Vector OA = (2; 1) ; |OA| = 2.2361
Vector OB = (6; 0) ; |OB| = 6
Scalar product OA .OB = 12
Angle ∠ AOB = 26°33'54″ = 0.4636 rad