Line slope calculator x-5y=-3


Enter coordinates of two different points:

Straight line given by points A[2; 1] and B[7; 2]

Calculation:

Slope-intercept form of line: y = 0.2x+0.6

Canonical form of the line equation: x-5y+3 = 0

Parametric form of the line equation:
x = 5t+2
y = t+1      ; t ∈ R

Slope: m = 0.2

Slope angle of line: φ = 11°18'36″ = 0.1974 rad

X intercept: x0 = -3

Y intercept: y0 = q = 0.6

Distance line from the origin: d0 = 0.5883

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; 1)

Normal vector: n = (1; -5)

Midpoint of the segment AB: M = [4.5; 1.5]

Perpendicular Bisector equation: 5x+y-24 = 0


Vector OA = (2; 1) ;   |OA| = 2.2361
Vector OB = (7; 2) ;   |OB| = 7.2801
Scalar product OA .OB = 16
Angle ∠ AOB = 10°37'11″ = 0.1853 rad