Line slope calculator 4x-5y=3
Straight line given by points A[2; 1] and B[7; 5]
Calculation:
Slope: m = 0.8Slope-intercept form of line: y = 0.8x-0.6
Canonical form of the line equation: 4x-5y-3 = 0
Parametric form of the line equation:
x = 5t+2
y = 4t+1 ; t ∈ R
Slope angle of line: φ = 38°39'35″ = 0.6747 rad
X intercept: x0 = 0.75
Y intercept: y0 = q = -0.6
Distance line from the origin: d0 = 0.4685
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; 4)
Normal vector: n = (4; -5)
Midpoint of the segment AB: M = [4.5; 3]
Perpendicular Bisector equation: 5x+4y-34.5 = 0
Vector OA = (2; 1) ; |OA| = 2.2361
Vector OB = (7; 5) ; |OB| = 8.6023
Scalar product OA .OB = 19
Angle ∠ AOB = 8°58'21″ = 0.1566 rad