Line slope calculator 6x+8y=92


Enter coordinates of two different points:

Straight line given by points A[2; 10] and B[10; 4]

Calculation:

Slope-intercept form of line: y = -0.75x+11.5

Canonical form of the line equation: 6x+8y-92 = 0

Parametric form of the line equation:
x = 8t+2
y = -6t+10      ; t ∈ R

Slope: m = -0.75

Slope angle of line: φ = -36°52'12″ = -0.6435 rad

X intercept: x0 = 15.3333

Y intercept: y0 = q = 11.5

Distance line from the origin: d0 = 9.2

The length of the segment AB: |AB| = 10

Vector: AB = (8; -6)

Normal vector: n = (6; 8)

Midpoint of the segment AB: M = [6; 7]

Perpendicular Bisector equation: 8x-6y-6 = 0


Vector OA = (2; 10) ;   |OA| = 10.198
Vector OB = (10; 4) ;   |OB| = 10.7703
Scalar product OA .OB = 60
Angle ∠ AOB = 56°53'19″ = 0.9929 rad