Line slope calculator 5x+8y=90
Straight line given by points A[2; 10] and B[10; 5]
Calculation:
Slope: m = -0.625Slope-intercept form of line: y = -0.625x+11.25
Canonical form of the line equation: 5x+8y-90 = 0
Parametric form of the line equation:
x = 8t+2
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -32°19″ = -0.5586 rad
X intercept: x0 = 18
Y intercept: y0 = q = 11.25
Distance line from the origin: d0 = 9.54
The length of the segment AB: |AB| = 9.434
Vector: AB = (8; -5)
Normal vector: n = (5; 8)
Midpoint of the segment AB: M = [6; 7.5]
Perpendicular Bisector equation: 8x-5y-10.5 = 0
Vector OA = (2; 10) ; |OA| = 10.198
Vector OB = (10; 5) ; |OB| = 11.1803
Scalar product OA .OB = 70
Angle ∠ AOB = 52°7'30″ = 0.9098 rad