Line slope calculator 10x+y=30


Enter coordinates of two different points:

Straight line given by points A[2; 10] and B[3; 0]

Calculation:

Slope-intercept form of line: y = -10x+30

Canonical form of the line equation: 10x+y-30 = 0

Parametric form of the line equation:
x = t+2
y = -10t+10      ; t ∈ R

Slope: m = -10

Slope angle of line: φ = -84°17'22″ = -1.4711 rad

X intercept: x0 = 3

Y intercept: y0 = q = 30

Distance line from the origin: d0 = 2.9851

The length of the segment AB: |AB| = 10.0499

Vector: AB = (1; -10)

Normal vector: n = (10; 1)

Midpoint of the segment AB: M = [2.5; 5]

Perpendicular Bisector equation: x-10y+47.5 = 0


Vector OA = (2; 10) ;   |OA| = 10.198
Vector OB = (3; 0) ;   |OB| = 3
Scalar product OA .OB = 6
Angle ∠ AOB = 78°41'24″ = 1.3734 rad