Line slope calculator 10x+y=30
Straight line given by points A[2; 10] and B[3; 0]
Calculation:
Slope: m = -10Slope-intercept form of line: y = -10x+30
Canonical form of the line equation: 10x+y-30 = 0
Parametric form of the line equation:
x = t+2
y = -10t+10 ; t ∈ R
Slope angle of line: φ = -84°17'22″ = -1.4711 rad
X intercept: x0 = 3
Y intercept: y0 = q = 30
Distance line from the origin: d0 = 2.9851
The length of the segment AB: |AB| = 10.0499
Vector: AB = (1; -10)
Normal vector: n = (10; 1)
Midpoint of the segment AB: M = [2.5; 5]
Perpendicular Bisector equation: x-10y+47.5 = 0
Vector OA = (2; 10) ; |OA| = 10.198
Vector OB = (3; 0) ; |OB| = 3
Scalar product OA .OB = 6
Angle ∠ AOB = 78°41'24″ = 1.3734 rad