Line slope calculator 9x+y=28


Enter coordinates of two different points:

Straight line given by points A[2; 10] and B[3; 1]

Calculation:

Slope-intercept form of line: y = -9x+28

Canonical form of the line equation: 9x+y-28 = 0

Parametric form of the line equation:
x = t+2
y = -9t+10      ; t ∈ R

Slope: m = -9

Slope angle of line: φ = -83°39'35″ = -1.4601 rad

X intercept: x0 = 3.1111

Y intercept: y0 = q = 28

Distance line from the origin: d0 = 3.0921

The length of the segment AB: |AB| = 9.0554

Vector: AB = (1; -9)

Normal vector: n = (9; 1)

Midpoint of the segment AB: M = [2.5; 5.5]

Perpendicular Bisector equation: x-9y+47 = 0


Vector OA = (2; 10) ;   |OA| = 10.198
Vector OB = (3; 1) ;   |OB| = 3.1623
Scalar product OA .OB = 16
Angle ∠ AOB = 60°15'18″ = 1.0517 rad