Line slope calculator 5x+y=20
Straight line given by points A[2; 10] and B[3; 5]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+20
Canonical form of the line equation: 5x+y-20 = 0
Parametric form of the line equation:
x = t+2
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 4
Y intercept: y0 = q = 20
Distance line from the origin: d0 = 3.9223
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [2.5; 7.5]
Perpendicular Bisector equation: x-5y+35 = 0
Vector OA = (2; 10) ; |OA| = 10.198
Vector OB = (3; 5) ; |OB| = 5.831
Scalar product OA .OB = 56
Angle ∠ AOB = 19°39'14″ = 0.343 rad