Line slope calculator 6x+2y=32


Enter coordinates of two different points:

Straight line given by points A[2; 10] and B[4; 4]

Calculation:

Slope-intercept form of line: y = -3x+16

Canonical form of the line equation: 6x+2y-32 = 0

Parametric form of the line equation:
x = 2t+2
y = -6t+10      ; t ∈ R

Slope: m = -3

Slope angle of line: φ = -71°33'54″ = -1.249 rad

X intercept: x0 = 5.3333

Y intercept: y0 = q = 16

Distance line from the origin: d0 = 5.0596

The length of the segment AB: |AB| = 6.3246

Vector: AB = (2; -6)

Normal vector: n = (6; 2)

Midpoint of the segment AB: M = [3; 7]

Perpendicular Bisector equation: 2x-6y+36 = 0


Vector OA = (2; 10) ;   |OA| = 10.198
Vector OB = (4; 4) ;   |OB| = 5.6569
Scalar product OA .OB = 48
Angle ∠ AOB = 33°41'24″ = 0.588 rad