Line slope calculator 5x+2y=30
Straight line given by points A[2; 10] and B[4; 5]
Calculation:
Slope: m = -2.5Slope-intercept form of line: y = -2.5x+15
Canonical form of the line equation: 5x+2y-30 = 0
Parametric form of the line equation:
x = 2t+2
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -68°11'55″ = -1.1903 rad
X intercept: x0 = 6
Y intercept: y0 = q = 15
Distance line from the origin: d0 = 5.5709
The length of the segment AB: |AB| = 5.3852
Vector: AB = (2; -5)
Normal vector: n = (5; 2)
Midpoint of the segment AB: M = [3; 7.5]
Perpendicular Bisector equation: 2x-5y+31.5 = 0
Vector OA = (2; 10) ; |OA| = 10.198
Vector OB = (4; 5) ; |OB| = 6.4031
Scalar product OA .OB = 58
Angle ∠ AOB = 27°21' = 0.4773 rad