Line slope calculator x+y=12
Straight line given by points A[2; 10] and B[4; 8]
Calculation:
Slope: m = -1Slope-intercept form of line: y = -x+12
Canonical form of the line equation: x+y-12 = 0
Parametric form of the line equation:
x = t+2
y = -t+10 ; t ∈ R
Slope angle of line: φ = -45° = -0.7854 rad
X intercept: x0 = 12
Y intercept: y0 = q = 12
Distance line from the origin: d0 = 8.4853
The length of the segment AB: |AB| = 2.8284
Vector: AB = (2; -2)
Normal vector: n = (1; 1)
Midpoint of the segment AB: M = [3; 9]
Perpendicular Bisector equation: 2x-2y+12 = 0
Vector OA = (2; 10) ; |OA| = 10.198
Vector OB = (4; 8) ; |OB| = 8.9443
Scalar product OA .OB = 88
Angle ∠ AOB = 15°15'18″ = 0.2663 rad