Line slope calculator 10x+3y=50
Straight line given by points A[2; 10] and B[5; 0]
Calculation:
Slope: m = -3.3333Slope-intercept form of line: y = -3.3333x+16.6667
Canonical form of the line equation: 10x+3y-50 = 0
Parametric form of the line equation:
x = 3t+2
y = -10t+10 ; t ∈ R
Slope angle of line: φ = -73°18'3″ = -1.2793 rad
X intercept: x0 = 5
Y intercept: y0 = q = 16.6667
Distance line from the origin: d0 = 4.7891
The length of the segment AB: |AB| = 10.4403
Vector: AB = (3; -10)
Normal vector: n = (10; 3)
Midpoint of the segment AB: M = [3.5; 5]
Perpendicular Bisector equation: 3x-10y+39.5 = 0
Vector OA = (2; 10) ; |OA| = 10.198
Vector OB = (5; 0) ; |OB| = 5
Scalar product OA .OB = 10
Angle ∠ AOB = 78°41'24″ = 1.3734 rad