Line slope calculator 4x+3y=38
Straight line given by points A[2; 10] and B[5; 6]
Calculation:
Slope: m = -1.3333Slope-intercept form of line: y = -1.3333x+12.6667
Canonical form of the line equation: 4x+3y-38 = 0
Parametric form of the line equation:
x = 3t+2
y = -4t+10 ; t ∈ R
Slope angle of line: φ = -53°7'48″ = -0.9273 rad
X intercept: x0 = 9.5
Y intercept: y0 = q = 12.6667
Distance line from the origin: d0 = 7.6
The length of the segment AB: |AB| = 5
Vector: AB = (3; -4)
Normal vector: n = (4; 3)
Midpoint of the segment AB: M = [3.5; 8]
Perpendicular Bisector equation: 3x-4y+21.5 = 0
Vector OA = (2; 10) ; |OA| = 10.198
Vector OB = (5; 6) ; |OB| = 7.8102
Scalar product OA .OB = 70
Angle ∠ AOB = 28°29'44″ = 0.4973 rad