Line slope calculator 6x+4y=52


Enter coordinates of two different points:

Straight line given by points A[2; 10] and B[6; 4]

Calculation:

Slope-intercept form of line: y = -1.5x+13

Canonical form of the line equation: 6x+4y-52 = 0

Parametric form of the line equation:
x = 4t+2
y = -6t+10      ; t ∈ R

Slope: m = -1.5

Slope angle of line: φ = -56°18'36″ = -0.9828 rad

X intercept: x0 = 8.6667

Y intercept: y0 = q = 13

Distance line from the origin: d0 = 7.2111

The length of the segment AB: |AB| = 7.2111

Vector: AB = (4; -6)

Normal vector: n = (6; 4)

Midpoint of the segment AB: M = [4; 7]

Perpendicular Bisector equation: 4x-6y+26 = 0


Vector OA = (2; 10) ;   |OA| = 10.198
Vector OB = (6; 4) ;   |OB| = 7.2111
Scalar product OA .OB = 52
Angle ∠ AOB = 45° = 0.7854 rad