Line slope calculator 6x+4y=52
Straight line given by points A[2; 10] and B[6; 4]
Calculation:
Slope: m = -1.5Slope-intercept form of line: y = -1.5x+13
Canonical form of the line equation: 6x+4y-52 = 0
Parametric form of the line equation:
x = 4t+2
y = -6t+10 ; t ∈ R
Slope angle of line: φ = -56°18'36″ = -0.9828 rad
X intercept: x0 = 8.6667
Y intercept: y0 = q = 13
Distance line from the origin: d0 = 7.2111
The length of the segment AB: |AB| = 7.2111
Vector: AB = (4; -6)
Normal vector: n = (6; 4)
Midpoint of the segment AB: M = [4; 7]
Perpendicular Bisector equation: 4x-6y+26 = 0
Vector OA = (2; 10) ; |OA| = 10.198
Vector OB = (6; 4) ; |OB| = 7.2111
Scalar product OA .OB = 52
Angle ∠ AOB = 45° = 0.7854 rad