Line slope calculator 5x+4y=50


Enter coordinates of two different points:

Straight line given by points A[2; 10] and B[6; 5]

Calculation:

Slope-intercept form of line: y = -1.25x+12.5

Canonical form of the line equation: 5x+4y-50 = 0

Parametric form of the line equation:
x = 4t+2
y = -5t+10      ; t ∈ R

Slope: m = -1.25

Slope angle of line: φ = -51°20'25″ = -0.8961 rad

X intercept: x0 = 10

Y intercept: y0 = q = 12.5

Distance line from the origin: d0 = 7.8087

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; -5)

Normal vector: n = (5; 4)

Midpoint of the segment AB: M = [4; 7.5]

Perpendicular Bisector equation: 4x-5y+21.5 = 0


Vector OA = (2; 10) ;   |OA| = 10.198
Vector OB = (6; 5) ;   |OB| = 7.8102
Scalar product OA .OB = 62
Angle ∠ AOB = 38°53'4″ = 0.6787 rad