Line slope calculator 6x+5y=62
Straight line given by points A[2; 10] and B[7; 4]
Calculation:
Slope: m = -1.2Slope-intercept form of line: y = -1.2x+12.4
Canonical form of the line equation: 6x+5y-62 = 0
Parametric form of the line equation:
x = 5t+2
y = -6t+10 ; t ∈ R
Slope angle of line: φ = -50°11'40″ = -0.8761 rad
X intercept: x0 = 10.3333
Y intercept: y0 = q = 12.4
Distance line from the origin: d0 = 7.9383
The length of the segment AB: |AB| = 7.8102
Vector: AB = (5; -6)
Normal vector: n = (6; 5)
Midpoint of the segment AB: M = [4.5; 7]
Perpendicular Bisector equation: 5x-6y+19.5 = 0
Vector OA = (2; 10) ; |OA| = 10.198
Vector OB = (7; 4) ; |OB| = 8.0623
Scalar product OA .OB = 54
Angle ∠ AOB = 48°56'43″ = 0.8543 rad