Line slope calculator x+8y=18
Straight line given by points A[2; 2] and B[10; 1]
Calculation:
Slope: m = -0.125Slope-intercept form of line: y = -0.125x+2.25
Canonical form of the line equation: x+8y-18 = 0
Parametric form of the line equation:
x = 8t+2
y = -t+2 ; t ∈ R
Slope angle of line: φ = -7°7'30″ = -0.1244 rad
X intercept: x0 = 18
Y intercept: y0 = q = 2.25
Distance line from the origin: d0 = 2.2326
The length of the segment AB: |AB| = 8.0623
Vector: AB = (8; -1)
Normal vector: n = (1; 8)
Midpoint of the segment AB: M = [6; 1.5]
Perpendicular Bisector equation: 8x-y-46.5 = 0
Vector OA = (2; 2) ; |OA| = 2.8284
Vector OB = (10; 1) ; |OB| = 10.0499
Scalar product OA .OB = 22
Angle ∠ AOB = 39°17'22″ = 0.6857 rad