Line slope calculator 2x+3y=10


Enter coordinates of two different points:

Straight line given by points A[2; 2] and B[5; 0]

Calculation:

Slope-intercept form of line: y = -0.6667x+3.3333

Canonical form of the line equation: 2x+3y-10 = 0

Parametric form of the line equation:
x = 3t+2
y = -2t+2      ; t ∈ R

Slope: m = -0.6667

Slope angle of line: φ = -33°41'24″ = -0.588 rad

X intercept: x0 = 5

Y intercept: y0 = q = 3.3333

Distance line from the origin: d0 = 2.7735

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; -2)

Normal vector: n = (2; 3)

Midpoint of the segment AB: M = [3.5; 1]

Perpendicular Bisector equation: 3x-2y-8.5 = 0


Vector OA = (2; 2) ;   |OA| = 2.8284
Vector OB = (5; 0) ;   |OB| = 5
Scalar product OA .OB = 10
Angle ∠ AOB = 45° = 0.7854 rad