Line slope calculator x+4y=10


Enter coordinates of two different points:

Straight line given by points A[2; 2] and B[6; 1]

Calculation:

Slope-intercept form of line: y = -0.25x+2.5

Canonical form of the line equation: x+4y-10 = 0

Parametric form of the line equation:
x = 4t+2
y = -t+2      ; t ∈ R

Slope: m = -0.25

Slope angle of line: φ = -14°2'10″ = -0.245 rad

X intercept: x0 = 10

Y intercept: y0 = q = 2.5

Distance line from the origin: d0 = 2.4254

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; -1)

Normal vector: n = (1; 4)

Midpoint of the segment AB: M = [4; 1.5]

Perpendicular Bisector equation: 4x-y-14.5 = 0


Vector OA = (2; 2) ;   |OA| = 2.8284
Vector OB = (6; 1) ;   |OB| = 6.0828
Scalar product OA .OB = 14
Angle ∠ AOB = 35°32'16″ = 0.6202 rad