Line slope calculator x-4y=-6
Straight line given by points A[2; 2] and B[6; 3]
Calculation:
Slope: m = 0.25Slope-intercept form of line: y = 0.25x+1.5
Canonical form of the line equation: x-4y+6 = 0
Parametric form of the line equation:
x = 4t+2
y = t+2 ; t ∈ R
Slope angle of line: φ = 14°2'10″ = 0.245 rad
X intercept: x0 = -6
Y intercept: y0 = q = 1.5
Distance line from the origin: d0 = 1.4552
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; 1)
Normal vector: n = (1; -4)
Midpoint of the segment AB: M = [4; 2.5]
Perpendicular Bisector equation: 4x+y-18.5 = 0
Vector OA = (2; 2) ; |OA| = 2.8284
Vector OB = (6; 3) ; |OB| = 6.7082
Scalar product OA .OB = 18
Angle ∠ AOB = 18°26'6″ = 0.3218 rad