Line slope calculator x-4y=-6


Enter coordinates of two different points:

Straight line given by points A[2; 2] and B[6; 3]

Calculation:

Slope-intercept form of line: y = 0.25x+1.5

Canonical form of the line equation: x-4y+6 = 0

Parametric form of the line equation:
x = 4t+2
y = t+2      ; t ∈ R

Slope: m = 0.25

Slope angle of line: φ = 14°2'10″ = 0.245 rad

X intercept: x0 = -6

Y intercept: y0 = q = 1.5

Distance line from the origin: d0 = 1.4552

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; 1)

Normal vector: n = (1; -4)

Midpoint of the segment AB: M = [4; 2.5]

Perpendicular Bisector equation: 4x+y-18.5 = 0


Vector OA = (2; 2) ;   |OA| = 2.8284
Vector OB = (6; 3) ;   |OB| = 6.7082
Scalar product OA .OB = 18
Angle ∠ AOB = 18°26'6″ = 0.3218 rad