Line slope calculator x+5y=12
Straight line given by points A[2; 2] and B[7; 1]
Calculation:
Slope: m = -0.2Slope-intercept form of line: y = -0.2x+2.4
Canonical form of the line equation: x+5y-12 = 0
Parametric form of the line equation:
x = 5t+2
y = -t+2 ; t ∈ R
Slope angle of line: φ = -11°18'36″ = -0.1974 rad
X intercept: x0 = 12
Y intercept: y0 = q = 2.4
Distance line from the origin: d0 = 2.3534
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; -1)
Normal vector: n = (1; 5)
Midpoint of the segment AB: M = [4.5; 1.5]
Perpendicular Bisector equation: 5x-y-21 = 0
Vector OA = (2; 2) ; |OA| = 2.8284
Vector OB = (7; 1) ; |OB| = 7.0711
Scalar product OA .OB = 16
Angle ∠ AOB = 36°52'12″ = 0.6435 rad