Line slope calculator x+6y=14
Straight line given by points A[2; 2] and B[8; 1]
Calculation:
Slope: m = -0.1667Slope-intercept form of line: y = -0.1667x+2.3333
Canonical form of the line equation: x+6y-14 = 0
Parametric form of the line equation:
x = 6t+2
y = -t+2 ; t ∈ R
Slope angle of line: φ = -9°27'44″ = -0.1651 rad
X intercept: x0 = 14
Y intercept: y0 = q = 2.3333
Distance line from the origin: d0 = 2.3016
The length of the segment AB: |AB| = 6.0828
Vector: AB = (6; -1)
Normal vector: n = (1; 6)
Midpoint of the segment AB: M = [5; 1.5]
Perpendicular Bisector equation: 6x-y-28.5 = 0
Vector OA = (2; 2) ; |OA| = 2.8284
Vector OB = (8; 1) ; |OB| = 8.0623
Scalar product OA .OB = 18
Angle ∠ AOB = 37°52'30″ = 0.661 rad