Line slope calculator x+7y=16


Enter coordinates of two different points:

Straight line given by points A[2; 2] and B[9; 1]

Calculation:

Slope-intercept form of line: y = -0.1429x+2.2857

Canonical form of the line equation: x+7y-16 = 0

Parametric form of the line equation:
x = 7t+2
y = -t+2      ; t ∈ R

Slope: m = -0.1429

Slope angle of line: φ = -8°7'48″ = -0.1419 rad

X intercept: x0 = 16

Y intercept: y0 = q = 2.2857

Distance line from the origin: d0 = 2.2627

The length of the segment AB: |AB| = 7.0711

Vector: AB = (7; -1)

Normal vector: n = (1; 7)

Midpoint of the segment AB: M = [5.5; 1.5]

Perpendicular Bisector equation: 7x-y-37 = 0


Vector OA = (2; 2) ;   |OA| = 2.8284
Vector OB = (9; 1) ;   |OB| = 9.0554
Scalar product OA .OB = 20
Angle ∠ AOB = 38°39'35″ = 0.6747 rad