Line slope calculator 3x+8y=30
Straight line given by points A[2; 3] and B[10; 0]
Calculation:
Slope: m = -0.375Slope-intercept form of line: y = -0.375x+3.75
Canonical form of the line equation: 3x+8y-30 = 0
Parametric form of the line equation:
x = 8t+2
y = -3t+3 ; t ∈ R
Slope angle of line: φ = -20°33'22″ = -0.3588 rad
X intercept: x0 = 10
Y intercept: y0 = q = 3.75
Distance line from the origin: d0 = 3.5112
The length of the segment AB: |AB| = 8.544
Vector: AB = (8; -3)
Normal vector: n = (3; 8)
Midpoint of the segment AB: M = [6; 1.5]
Perpendicular Bisector equation: 8x-3y-43.5 = 0
Vector OA = (2; 3) ; |OA| = 3.6056
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 20
Angle ∠ AOB = 56°18'36″ = 0.9828 rad