Line slope calculator 2x+3y=13
Straight line given by points A[2; 3] and B[5; 1]
Calculation:
Slope: m = -0.6667Slope-intercept form of line: y = -0.6667x+4.3333
Canonical form of the line equation: 2x+3y-13 = 0
Parametric form of the line equation:
x = 3t+2
y = -2t+3 ; t ∈ R
Slope angle of line: φ = -33°41'24″ = -0.588 rad
X intercept: x0 = 6.5
Y intercept: y0 = q = 4.3333
Distance line from the origin: d0 = 3.6056
The length of the segment AB: |AB| = 3.6056
Vector: AB = (3; -2)
Normal vector: n = (2; 3)
Midpoint of the segment AB: M = [3.5; 2]
Perpendicular Bisector equation: 3x-2y-6.5 = 0
Vector OA = (2; 3) ; |OA| = 3.6056
Vector OB = (5; 1) ; |OB| = 5.099
Scalar product OA .OB = 13
Angle ∠ AOB = 45° = 0.7854 rad