Line slope calculator 2x+3y=13


Enter coordinates of two different points:

Straight line given by points A[2; 3] and B[5; 1]

Calculation:

Slope-intercept form of line: y = -0.6667x+4.3333

Canonical form of the line equation: 2x+3y-13 = 0

Parametric form of the line equation:
x = 3t+2
y = -2t+3      ; t ∈ R

Slope: m = -0.6667

Slope angle of line: φ = -33°41'24″ = -0.588 rad

X intercept: x0 = 6.5

Y intercept: y0 = q = 4.3333

Distance line from the origin: d0 = 3.6056

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; -2)

Normal vector: n = (2; 3)

Midpoint of the segment AB: M = [3.5; 2]

Perpendicular Bisector equation: 3x-2y-6.5 = 0


Vector OA = (2; 3) ;   |OA| = 3.6056
Vector OB = (5; 1) ;   |OB| = 5.099
Scalar product OA .OB = 13
Angle ∠ AOB = 45° = 0.7854 rad