Line slope calculator 3x+4y=18


Enter coordinates of two different points:

Straight line given by points A[2; 3] and B[6; 0]

Calculation:

Slope-intercept form of line: y = -0.75x+4.5

Canonical form of the line equation: 3x+4y-18 = 0

Parametric form of the line equation:
x = 4t+2
y = -3t+3      ; t ∈ R

Slope: m = -0.75

Slope angle of line: φ = -36°52'12″ = -0.6435 rad

X intercept: x0 = 6

Y intercept: y0 = q = 4.5

Distance line from the origin: d0 = 3.6

The length of the segment AB: |AB| = 5

Vector: AB = (4; -3)

Normal vector: n = (3; 4)

Midpoint of the segment AB: M = [4; 1.5]

Perpendicular Bisector equation: 4x-3y-11.5 = 0


Vector OA = (2; 3) ;   |OA| = 3.6056
Vector OB = (6; 0) ;   |OB| = 6
Scalar product OA .OB = 12
Angle ∠ AOB = 56°18'36″ = 0.9828 rad