Line slope calculator 3x+4y=18
Straight line given by points A[2; 3] and B[6; 0]
Calculation:
Slope: m = -0.75Slope-intercept form of line: y = -0.75x+4.5
Canonical form of the line equation: 3x+4y-18 = 0
Parametric form of the line equation:
x = 4t+2
y = -3t+3 ; t ∈ R
Slope angle of line: φ = -36°52'12″ = -0.6435 rad
X intercept: x0 = 6
Y intercept: y0 = q = 4.5
Distance line from the origin: d0 = 3.6
The length of the segment AB: |AB| = 5
Vector: AB = (4; -3)
Normal vector: n = (3; 4)
Midpoint of the segment AB: M = [4; 1.5]
Perpendicular Bisector equation: 4x-3y-11.5 = 0
Vector OA = (2; 3) ; |OA| = 3.6056
Vector OB = (6; 0) ; |OB| = 6
Scalar product OA .OB = 12
Angle ∠ AOB = 56°18'36″ = 0.9828 rad